Subject: Re: [xsl] difference between an integer and current-dateTime() From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 30 Mar 2020 12:01:24 -0000 |
> The following finally works for me, > > > <xsl:function name="fn0:minsFromdiffDTduration" as="xs:decimal"> > <xsl:param name="diffDTduration" as="xs:dayTimeDuration"/> > > <xsl:variable name="yrsDuration" select="years-from-duration($diffDTduration)"/> > <xsl:variable name="mnthsDuration" select="months-from-duration($diffDTduration)"/> > <xsl:variable name="daysDuration" select="days-from-duration($diffDTduration)"/> > <xsl:variable name="hrsDuration" select="hours-from-duration($diffDTduration)"/> > <xsl:variable name="mnsDuration" select="minutes-from-duration($diffDTduration)"/> > <xsl:variable name="secsDuration" select="seconds-from-duration($diffDTduration)"/> > > <xsl:variable name="totalSecs" select="$yrsDuration * 365 * 24 * 60 + $mnthsDuration * 30 * 24 * 60 + > $daysDuration * 24 * 60 + $hrsDuration * 60 + $mnsDuration + > $secsDuration div 60" /> > <xsl:sequence select="$totalSecs"/> > > </xsl:function> > This seems very convoluted. For a start, it assumes that every month is 30 days long, though this error doesn't really matter since your input is a dayTimeDuration so the number of years and months will always be zero. But there's a much simpler way of doing it (which I'm sure has been suggested): divide the supplied dayTimeDuration by xs:dayTimeDuration('PT1S') (using the div operator) to get the number of seconds. Michael Kay Saxonica
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