Re: [xsl] XSLT program outputs a series of items, how to insert newlines between each item?

["Graham Heath graham.heath@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi Roger,

I always use a variable for CR and as Martin says an xsl:value-of.
I also pass a parameter in with OS so that CR gets either Windows or Linux
separators..

Hope this hells
Graham

On Thu, 25 Jun 2020 at 15:16, Martin Honnen martin.honnen@xxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>
> On 25.06.2020 15:11, Roger L Costello costello@xxxxxxxxx wrote:
> > Hi Folks,
> >
> > My XSLT program has a loop. Each iteration outputs an item. I want each
> item on a new line. The following works. Is there a better way to insert
> newlines than by using xsl:text with the end tag on the next line?  /Roger
> >
> > <xsl:output method="text" />
> >
> > <xsl:template match="/">
> >      <xsl:for-each select="//xs:simpleType[@name eq
> 'DatumCode']//xs:enumeration">
> >          <xsl:value-of select="concat(@value, ' (',
> xs:annotation/xs:documentation, ')')/>
> > <xsl:text>
> > </xsl:text>
> >      </xsl:for-each>
> > </xsl:template>
>
>
> I would use xsl:value-of separator
>
>
> <xsl:value-of select="//xs:simpleType[@name eq
> 'DatumCode']//xs:enumeration/concat(@value, ' (',
> xs:annotation/xs:documentation, ')')" separator="&#10;"/>