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Subject: Re: [xsl] XQuery/XPath 3.1: Node List to Node Set ("distinct nodes") From: "Liam R. E. Quin liam@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 29 Dec 2021 19:47:44 -0000 |
On Wed, 2021-12-29 at 19:06 +0000, Dimitre Novatchev dnovatchev@xxxxxxxxx wrote: > On Wed, Dec 29, 2021 at 10:27 AM Martin Honnen martin.honnen@xxxxxxx < > xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > I am happy to state that the provided solution produces the correct > result > on all currently-existing XPath engines :) Does that include Oracle and DB2? What if the XPath expression is used inside an "unordered" expression? Probably it works well enough in practice; if it was part of a library i was distributing, at the very least i'd want to document that the order is not guaranteed. Liam -- Liam Quin,B https://www.delightfulcomputing.com/ Available for XML/Document/Information Architecture/XSLT/ XSL/XQuery/Web/Text Processing/A11Y training, work & consulting. Barefoot Web-slave, antique illustrations: B http://www.fromoldbooks.org
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