Re: [xsl] How to efficiently obtain the first 10 records of a file with over 2 million records?

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 19.07.2023 17:38, Martin Honnen martin.honnen@xxxxxx wrote:
> On 19.07.2023 17:16, Roger L Costello costello@xxxxxxxxx wrote:
> > I have an XML file containing over 2 million <record> elements. I
> > want to obtain the first 10 <record> elements.
> >
> > Here's how I did it:
> >
> > <xsl:for-each select="/Document/record[position() le 10]">
> > B B B B  <xsl:sequence select="."/>
> > </xsl:for-each>
> >
> > I ran it and it took a long time to complete. I am guessing that the
> > XSLT processor is iterating over all 2 million <record> elements.
> > Yes?B  How to write the XSLT code so that the XSLT processor stops
> > iterating upon processing the first 10 <record> elements?
>
>
>
>
> I am not sure whether you need an explicit
>
>
> <xsl:mode streamable="yes"/>
>
> <xsl:template match="/">
>
> B  <xsl:iterate select="Document/record">
>
> B B B  <xsl:copy-of select="."/>
>
> B B  <xsl:if test="position() eq 10">
>
> B B B B  <xsl:break/>
>
> B B  </xsl:if>
>
> B  </xsl:iterate>
>
> </xsl:template>
>
>
> to ensure that Saxon stops processing after the 10 records, run from the
> command line with -t and look for an early exit message to confirm.

I checked with the documentation
https://www.saxonica.com/html/documentation12/streaming/partial-reading.html
and an example, yes, it looks as if to get Saxon to stop parsing the
complete document the xsl:iterate/xsl:break is needed.