Re: [xsl] Resolving character entities

["Michael Kay michaelkay90@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Phase 1: the parser converts character entities into characters. Phase 2: the
XSLT processor manipulates characters. Phase 3: the XSLT processor passes
characters to the serializer for output, which escapes them if they need
escaping. There's no way that phase 3 can be influenced by what happened in
phase 1.

Michael Kay
Saxonica



> On 15 Feb 2024, at 15:52, rick@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hi All,
>
> I have this as the input:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <!DOCTYPE subtask [
> <!ENTITY lt "&#38;">
> <!ENTITY gt "&#62;">
> <!ENTITY amp "&#38;">
> ]>
>
> <subtask>
>     <title>General Information</title>
>     <prcitem1>
>         <prcitem>
>             <para>This document provides &lt; repair instructions &amp; for
the Fire Extinguisher components.</para>
>         </prcitem>
>     </prcitem1>
> </subtask>
>
> I want all of the entities to be resolved when I transform the file. This is
my stylesheet:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>     xmlns:xs="http://www.w3.org/2001/XMLSchema";
>     xmlns:math="http://www.w3.org/2005/xpath-functions/math";
>     exclude-result-prefixes="xs math"
>     version="3.0" expand-text="yes">
>
>     <xsl:output indent="yes"/>
>
>     <xsl:template match="/">
>         <xsl:apply-templates/>
>     </xsl:template>
>
>     <xsl:mode on-no-match="shallow-copy"/>
>
> </xsl:stylesheet>
>
> This is my output:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <subtask>
>    <title>General Information</title>
>    <prcitem1>
>       <prcitem>
>          <para>This document provides &lt; repair instructions &amp; for the
Fire Extinguisher components.</para>
>       </prcitem>
>    </prcitem1>
> </subtask>
>
> I was thinking that my $lt; should have been substituted with &#38;, etc.
Does it not matter because these are bvalidb XML entities? Thank you.
>
> Rick
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