Subject: RE: [stella] RAM usage From: adavie@xxxxxxxxxx Date: Wed, 21 Jun 2000 12:08:42 +1000 |
Yes I'm aware 7 x 32 = 224. Having a busy day at work. 224/8 = 28 bytes A -----Original Message----- From: Andrew Davie Sent: Wednesday, June 21, 2000 10:44 AM To: 'stella@xxxxxxxxxxx' Subject: RE: [stella] RAM usage Why do you say (assume?) that Video Chess uses 64 bytes for board position? I could do it with 32 by simply having one byte for each PIECE, and recording its square number But each square only numbers from 0-63, so you only need 7 bits Haven't wee been thru all this before? 7 bits x 32 pieces = 214 bits / 8 = 27 bytes approx. I'm sure there are lots more efficient codings possible. A -----Original Message----- From: owner-stella@xxxxxxxxxxx [mailto:owner-stella@xxxxxxxxxxx]On Behalf Of Glenn Saunders Sent: Wednesday, June 21, 2000 10:19 AM To: stella@xxxxxxxxxxx Subject: [stella] RAM usage The TIA reference says there are 45 reserved hardware registers. These are mapped into the 128 bytes, right? So that means a game like Video Chess, which uses 64 bytes for board position, only has 19 free bytes for the program and the stack, right? Glenn Saunders - Producer - Cyberpunks Entertainment Personal homepage: http://www.geocities.com/Hollywood/1698 Cyberpunks Entertainment: http://cyberpunks.uni.cc -- Archives (includes files) at http://www.biglist.com/lists/stella/archives/ Unsub & more at http://www.biglist.com/lists/stella/ -- Archives (includes files) at http://www.biglist.com/lists/stella/archives/ Unsub & more at http://www.biglist.com/lists/stella/
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