> I am curious about something here. The 6507 has a 13-bit address
> bus. This comes out to 8192 bytes linear addressable. Don't these hex
> values jump around too much to fit within that address space?
Yes, as someone said, only the lower 13 bits of whatever the programmer
uses is actually implemented. The entirety(with I think a few _bytes_ of
exception) of the 8k is filled up. Chris' memory map should clear this
up.
Mark
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