Hi Thomas,
> Yes! (at least I think so ;-)
> (or are there constrains between the rows too?)
I don't think so at the moment. I'll see how they pan out.
> How quick do you need it? Do you want to calculate that on the fly?
I'm thinking of storing the values in RAM for a quick draw during the kernel but we'll see :)
> Else a simple loop should do.
> Here's some pseudo code:
>
> x = 18 // 19 not allowed due to reflected PF, right?
> do
> if newLadder() // (from random number generator)
> putLadder() // new ladder at x and x-1
> x = x - 4 // skip next 4 positions
> else
> x = x - 1 // check next position
> while x > 2
Don't I feel stupid. This seems so simple now. Thanks Thomas, I see what you're doing.
> Plus a check if there is at least one ladder.
There will always be at least one.
Take care,
Dennis
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