RE: counting and displaying with xsl?

Subject: RE: counting and displaying with xsl?
From: Sean Lockhart <SeanL@xxxxxxxxxxx>
Date: Wed, 7 Jun 2000 14:22:01 -0700
The following has worked for me before:

		<xsl:if expr="(childNumber(this) % 5) == 1">

-----Original Message-----
From: juggy@xxxxxxx [mailto:juggy@xxxxxxx]
Sent: Tuesday, June 06, 2000 5:07 PM
To: xsl-list@xxxxxxxxxxxxxxxx
Subject: counting and displaying with xsl?


Hi,

Is there any way to use xsl to count the number of items in my 
xml? I'd like to know this so I could arrange them according to their 
number (e.g. have a line break every 5 items).
I think of something like
<xsl:if "count > 5">
	ARRANGE NORMAL
<xsl:if-otherwise>
	LINEBREAK
	ARRANGE NORMAL
...

Juggy


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