Subject: Sorting across Multiple branches of XML From: "Chidester, Brice" <Brice.Chidester@xxxxxxxxx> Date: Fri, 9 Jun 2000 09:08:27 -0400 |
I'm wondering if it's possible to use the <xsl:sort> tag to sort elements that lie across multiple branches of my XML file. For instance, my XML might look as follows: <node_list> <hp> <hp_node> <node_name>aaa</node_name> <type>hp</type> </hp_node> <hp_node> <node_name>ccc</node_name> <type>hp</type> </hp_node> </hp> <sun> <sun_node> <node_name>bbb</node_name> <type>sun</type> </sun_node> </sun> </node_list> I currently have an xsl file that appears similar to this: <xsl:stylesheet> <xsl:template match="node_list"> <xsl:apply-templates> <xsl:sort order="descending" select="node_name"/> </xsl:apply-templates> </xsl:template> <xsl:template match="hp_node"> <xsl:value-of select="node_name"/> <xsl:value-of select="type"/> </xsl:template> <xsl:template match="sun_node"> <xsl:value-of select="node_name"/> <xsl:value-of select="type"/> </xsl:template> </xsl:stylesheet> Currently, my output appears like this: aaa hp ccc hp bbb sun Is there any way to make it appear like this?: aaa hp bbb sun ccc hp I'd really appreciate any suggestions anyone could offer. Thanks. Brice Chidester XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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