Subject: Problem using XSL From: "Stéphane Mamdy" <smamdy@xxxxxxxxxxxxx> Date: Fri, 9 Jun 2000 16:56:52 +0200 |
Hi, I amquite new in using XML. I have done an XML doc like this: <?xml version="1.0" encoding="ISO-8859-1" ?> <?xml:stylesheet type="text/xsl" href="liste_cron1.xsl"?> <LPlan> <Plan> <MOTEUR ID_MOTEUR="Agritest">Agritest</MOTEUR> <SITE ID_SITE="15">agrifirst</SITE> </Plan> <Plan> <MOTEUR ID_MOTEUR="Agritest - Altavista">Agritest - Altavista</MOTEUR> <SITE ID_SITE="15">agrifirst</SITE> </Plan> </LPlan> I have this XSL document: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl" xmlns="http://www.w3.org/TR/REC-html4.0" result-ns=""> <xsl:template match="/"> <html xmlns=""> <head> <link REL="stylesheet" TYPE="text/css" HREF="cell.css"/> </head> <body> <xsl:apply-templates select="LPlan"/> </body> </html> </xsl:template> <xsl:template match="LPlan"> <xsl:for-each select="Plan" order-by="SITE"> num de ligne <xsl:value-of select="position()" /> <p/> <xsl:value-of select="MOTEUR"/> <xsl:value-of select="SITE"/> </xsl:for-each> </xsl:template> </xsl:stylesheet> This line : num de ligne <xsl:value-of select="position()" /> doesnt work with IE5 ... Why ? I don't find any information about it.... Perhaps do i forget something ? Thanks for you help. Stéphane Mamdy. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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