Subject: RE: question with using Muenchian/xsl:key (Re: sort/group/count p robl em) From: Xiaocun Xu <XXu@xxxxxxxxxxxxxxxxxx> Date: Sat, 11 Nov 2000 18:17:21 -0500 |
My original code was trying exactly what you have suggested, but unfortunely it creates invalid XSL due to xsl:key is top-level element, so it can not be an element inside templates. Xiaocun -----Original Message----- From: Goetz Bock To: xsl-list@xxxxxxxxxxxxxxxx Sent: 11/11/00 3:33 PM Subject: Re: question with using Muenchian/xsl:key (Re: sort/group/count probl em) On Sat, Nov 11 '00 at 13:47, Xu, Xiaocun wrote: > [ ...] > key('items-by-itemid', @itemid) returns all items with the same @itemid in > the entire XML document. I just want all items with the same @itemid in > each of the itemlist element, how can I do that? What about creating the key inside the template that matches itemlist? <xsl:template match="itemlist"> <xsl:key ...> </xsl:template> Not tried, but shoud work, Goetz. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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