Subject: Change the value of a parameter in a template From: fredric larsson <fredric.larsson@xxxxxxxxxx> Date: Mon, 13 Nov 2000 16:52:14 +0100 |
Hi. I have got the same problem as Laurent has in his mail dated 6 Nov 2000 08:46:48 +0000 from e-mail address: "Ext.ZXSPRCR2A015@xxxxxxxxxx". Here is my problem: I want to compare XML-data with a value of a parameter in my XSL-stylesheet. XML-data looks like this: <wc:INSTANCE CLASS="Rel"> <Left>id11</Left> <Right>id12</Right> <OBID>id1</OBID> </wc:INSTANCE> <wc:INSTANCE CLASS="Rel"> <Left>id21</Left> <Right>id22</Right> <OBID>id2</OBID> </wc:INSTANCE> I've got a template, called "Relation", with two parameters: <xsl:param name="article" select='OBID'/> <xsl:param name="find"/> I call a new template called "findRelation" and apply the parameters: <xsl:call-template name="findRelation"> <xsl:with-param name="article" select="$article"/> <xsl:with-param name="find" select="$find"/> </xsl:call-template> In the template "findRelation" I compare the parameter "article" with the XML-data in a loop ("for-each"). When an element, <Left>, is equal to the parameter "article" I store the <Right> element in the parameter "find ": <xsl:template name="findRelation"> <xsl:param name="article"/> <xsl:param name="find"/> <xsl:for-each select="//wc:INSTANCE"> <xsl:if test="Left=$article"> <xsl:param name="find" select='Right'/> </xsl:if> </xsl:for-each> </xsl:template> Then I want to access the parameter "find", with its new value, from the calling template "Relation". Does anybody know how to do that? Regards Fredric XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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