Subject: Re: how to replace line-feeds with space? From: Mike Brown <mike@xxxxxxxx> Date: Tue, 14 Nov 2000 22:41:56 -0700 (MST) |
Chad Small wrote: > I found some info on dpawson's basic trouble-shooting under the Replace > link, but can't seem to make the transformation work. Actually, you're doing way too much work. If you're replacing a single character with a single character, all you need is the XPath function translate(). <xsl:template match="TITLE/text()"> <xsl:value-of select="translate(.,' ',' ')"/> </xsl:template> Using tail recursion and substrings is only necessary if you're doing substring replacement, or replacing characters with elements. - Mike ____________________________________________________________________ Mike J. Brown, software engineer at My XML/XSL resources: webb.net in Denver, Colorado, USA http://www.skew.org/xml/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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