RE: Pagination

[hemant18@xxxxxxxxxxxx]

hi

Thanks for your solution. But the problem is a bit more complex. I have on my page a drop down Select, which indicates the page number. I have written a javascript function that is called onChange= of the select object.

When the user selects a page number, lets say page number 4 the page should display records from 31-40. If the user presses page number 5 it should display records from 41-50 etc.

If I am on page number 4 which is displaying 31-40, pressing the PREV button I should get records from 
21-30, and pressing NEXT button should get me records from 41-50 etc.

I appreciate if you can help out in this , with a sample code and explanation



On Fri, 01 December 2000, Kay Michael wrote:

> 
> > How to do pagination using XSL. ?
> > 
> > I have many records which can go upto 500. I need to display 
> > 20 records on one page . By clicking NEXT butoon it should 
> > show me next 20 records and so on.
> 
> Write a template that uses match="item[position() mod 20 = 1]", and within
> this template, do for-each select = ". | following-sibling::item[position()
> < 20]".
> 
> Mike Kay 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list