Subject: Transformation from XML to Table Rows From: Estefan27@xxxxxxx Date: Mon, 04 Dec 2000 15:53:59 EST |
Greetings; I have an xml document with the following structure: <root> <topic id="1"> <topic_name>topic name</topic_name> <sub_topic id="1">subtopicname</sub_topic> <sub_topic id="2">subtopicname</sub_topic> <sub_topic id="3">subtopicname</sub_topic> </topic> <topic id="2"> <topic_name>topic name</topic_name> <sub_topic id="4">subtopicname</sub_topic> <sub_topic id="5">subtopicname</sub_topic> <sub_topic id="6">subtopicname</sub_topic> </topic> . . . </root> Can someone please show me how to make an XSLTransformation that will: --Transform the topic into html rows. 3 topics to row. (i want it flexible so that i can later change the xsl to 4 per row. therefore i wish to use something like <xsl:if test="position() mod 3 = 0"> </tr><tr> <!--naturally this gives an error--> </xsl:if> ) all the sub_topics must be presented below each corresponding topic name. Therefore I'm thinking about something along the lines of the following. ( I could be way off. if someone could help that would be great. <xsl:template match="/"> <table> <tr> <xsl:for-each select="root/topic"> <td><xsl:apply-templates select="displaytopic" /> </td> <xsl:for-each> </tr> </table> </xsl:template> <xsl:template match="displaytopic"> <xsl:element name="a"> <xsl:attribute name="href"> /anasppage.asp?id=<xsl:value-of select="@id"/> </xsl:attribute> <xsl:value-of select="topic_name" /> </xsl:element> <xsl:apply-templates select="display_related_sub_topic" /> </xsl:template> <xsl:template match="display_related_sub_topic"> <xsl:element name="a"> <xsl:attribute name="href"> /anasppage.asp?id=<xsl:value-of select="@id"/> </xsl:attribute> <xsl:value-of select="sub_topic" /> </xsl:element> <xsl:apply-templates select="sub_topic" /> </xsl:template> all guidance would be greatly appreciated. s XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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