Subject: [xsl] select distinct From: Richard Lander <rlander@xxxxxxxxxxxxx> Date: Fri, 15 Dec 2000 16:45:44 -0800 |
Hello, I'm having some trouble with selecting distinct nodes (no duplicates). I am using the following algorithm at the moment, which works, but am wondering if there is something more elegant. generate-id() seems too heavy-handed. <xsl:template name="element"> <xsl:param name="path"/> <xsl:for-each select="$path//xdr:element"> <xsl:if test="self::xdr:element[generate-id() = generate-id($path//xdr:element[@type = current()/@type][1])]"> <A href="javascript:element('{@type}')"> <xsl:value-of select="@type"/> </A> </xsl:if> </xsl:for-each> </xsl:template> I don't have my Mike Kay book beside me at the moment, so can't look for any tips on this likely well-documented problem. I will mention that the elements are not all siblings. Some are, some are further down. The input looks like: x x x y x x x y x x x x x I'm trying to get all the x elements with distinct @type values. Thanks, Rich XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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