Subject: [xsl] Ommitting value of a copied id-Attribute From: Yunus Karakaya <blackrock@xxxxxxx> Date: Wed, 20 Dec 2000 13:14:18 +0100 |
Dear People, I want to copy a node with all it's attributes and the values of the attributes except the id-attribute. I want also copy the id-attribute, but ommit the value of it. So I tried the usual way, but did some mistakes: 1. I match the node. Copy the node. 2. In this node, I apply templates on the attributes with select=@* and mode=attrcopy. 3. In this mode I match again @* and then can do the processing. Here I need some help of you. I couldn't manage to do. I tried above in the "apply-templates" with several XPath expressions, not worked. I tried with xsl-if, couldn't get it done. So can somebody of you please help me? Thank you very much. Yunus Karakaya XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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