Subject: RE: [xsl] performance of copying all source to result From: Evyatar_Kafkafi <evyatar@xxxxxxxxx> Date: Thu, 21 Dec 2000 12:28:46 +0200 |
Actually, I started with match="*", and only later tried the "a | applet | ..." approach. Unfortunately, both methods are slow and no method is quicker than the other. As to the copy-of advice, I'll try that. Evyatar -----Original Message----- From: David Carlisle [mailto:davidc@xxxxxxxxx] Sent: Thursday, December 21, 2000 11:55 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] performance of copying all source to result wouldn't match="*" be quicker than <xsl:template match=" a | applet | b | big | body | br | caption | cite | code | col | colgroup | dd | div | dl | dt | em | font | form | frame | frameset | head | h1 | h2 | h3 | h4 | h5 | h6 | hr | html | i | iframe | img | link | li | map | meta | noframes | ol | p | param | pre | s | script | small | span | strong | style | sub | sup | td | th | title | tr | tt | ul | var | table "> you can still overide that with more specific templates for elements you don't want to copy. Also, if there are any elements for which you want always want to copy the whole branch, you may find it quicker to use copy-of select="." rather than <xsl:copy and xsl:apply-templates. David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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