Subject: RE: [xsl] Maximum number of cells From: Kay Michael <Michael.Kay@xxxxxxx> Date: Tue, 2 Jan 2001 11:26:29 -0000 |
Mark Dudley: > Given the following XML: > > <table> > <row> > <cell>...</cell> > </row> > <row> > <cell>...</cell> > <cell>...</cell> > <cell>...</cell> > </row> > <row> > <cell>...</cell> > <cell>...</cell> > </row> > </table> > > I need to compare the number of cells in each row element and > get the count > of cell elements in the row that has the most (3 in this > case). there's no built in max and min functions; alternatives are: (a) sort, and find the first/last (b) recursive template (c) extension functions saxon:max(), saxon:min() Doing (a), with <table> as current node: <xsl:variable name="maxcells"> <xsl:for-each select="row"><xsl:sort select="count(cell)" order="descending"/> <xsl:if test="position()=1"><xsl:value-of select="count(cell)"/></xsl:if> </xsl:for-each> </xsl:variable> Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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