Subject: [xsl] Name of current node's parent? From: "Michael Lee" <mlee@xxxxxxxxxx> Date: Thu, 4 Jan 2001 09:21:26 +0800 |
Hi, I am new to the list and XSL. In an XSLT stylesheet I am currently working on, I want to compare the name of the current note's parent with a string using <xsl:if>. Let's say this is a fragment of an XML document: <a> <b></b> <b><c></c></b> <c></c> <a> Instead of using <xsl:template match="b/c"> </xsl:template> I want to use something like <xsl:template match="c"> <xsl:if test="boolean-expression"></xsl:if> </xsl:template> To check and see if the parent of <c> is <b> or not. However, I am not very familiar with XPath expressions and have no idea now to write the boolean expression inside <xsl:if>. Can someone help me? Michael Lee mlee@xxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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