Re: [xsl] using xsl:copy

Subject: Re: [xsl] using xsl:copy
From: Frank Hess <hess.frank@xxxxxx>
Date: Tue, 23 Jan 2001 18:19:44 +0100
Use:

<xsl:template match="/catalog/item">
        <xsl:apply-templates select="description"/>
</xsl:template>

<xsl:template match="description">
        <xsl:copy-of select="."/>
</xsl:template>


At 11:59 23.01.01 -0500, you wrote:


If I have an xml structure like this:

<catalog>
  <item>
       <description><b>A nice shoe</b></description>
  </item>
</catalog>

and my xsl looks like this:

<xsl:template match="/catalog/item">
        <xsl:copy-of select="description"/>
</xsl:template>


my HTML output is: <description><b>A nice shoe</b></description>


How can I output the html without the <description> tags? I wish to preserve the <b> tags which may or may not be there.

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list


XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list


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