RE: [xsl] Serious problems finding syntax

Subject: RE: [xsl] Serious problems finding syntax
From: Mulberry Technologies List Owner <xsl-list-owner@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 23 Jan 2001 16:39:34 -0500
Message-ID: <200101231540450141.15962F4C@xxxxxxxxxxxxx>
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Date: Tue, 23 Jan 2001 15:40:45 -0600
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From: "Gavin Landon" <gavin@xxxxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: [xsl] Serious problems finding syntax
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Thanks and Sorry, the XML was just a piece since it was too long. I just deleted the wrong Attribute for the demo. <g>..

When I put in both ways I get no data. I remove the IF and I get all data.

I want it to say something like:
IF PREVIOUS_PAGE is empty don't display Information...

<xsl:if test="@PREVIOUS_PAGE != ''"> I would guess, but nothing, not even an error occurs

I found a website:
http://www.zvon.org/xxl/XSLTreference/Output/index.html

But all examples are simple with no attributes. Doesn't anyone have a site showing XML and it's entirety?


*********** REPLY SEPARATOR ***********


On 1/23/01 at 12:47 PM Edmund Mitchell wrote:

Gavin

I don't see any PREVIOUS_QUERY attributes in your XML, so it's unlikely
they'll get selected. :>)
Try if test='string(@PREVIOUS_PAGE)' or stay with your @PREVIOUS_PAGE != ''
The data appears as it should when the test is removed because the default
templates are invoked.
I hope this helps
Edmund

<FOOTER>
	<CONTENT PREVIOUS_PAGE="" NEXT_PAGE="2"></CONTENT>
	<CONTENT PREVIOUS_PAGE="1" NEXT_PAGE="3"></CONTENT>
	<CONTENT PREVIOUS_PAGE="2" NEXT_PAGE="4"></CONTENT>
</FOOTER>


In my XSL I have : <xsl:for-each select="CONTENT"> <xsl:if test="@PREVIOUS_QUERY!=''"> <a><xsl:attribute name="href">default.asp<xsl:value-of select="@PREVIOUS_QUERY" /></xsl:attribute>Previous Page</a><br/> </xsl:if> </xsl:for-each>

This IF Statement causes NO DATA to appear.   Take out the If statement and
all data appears as it should.

--
Gavin Landon
Karland International
http://www.karland.com/



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-- Gavin Landon Karland International http://www.karland.com/

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