Subject: RE: [xsl] Getting the deepest node and calculating relative paths From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Thu, 25 Jan 2001 10:19:32 -0000 |
> I need to transform an XML that looks like: > > <Root> > <Paths> > <Path value="/Catalog/Department/Product/SKU"/> > <Path value="/Catalog/Department/@dept_id"/> > <Path value="/Catalog/Department/Product/Name"/> > <Path value="/Catalog/Department/Product/Price"/> > <Path value="/Catalog/Department/Product/Variant/Name"/> > </Paths> > </Root> > > to something that looks like: > > <Root> > > <LongestPath>/Catalog/Department/Product/Variant/Name</LongestPath> Would counting the number of "/" characters give you the right answer? You can do that as string-length($path) - string-length(translate($path, '/', '')) Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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