Subject: RE: [xsl] xsl to echo input xml From: "Kearney, Bryan" <bkearney@xxxxxxxxxx> Date: Thu, 25 Jan 2001 11:49:19 -0700 |
You want the identity transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!-- Match every node whether it is an element or an attribute --> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="/"> <xsl:apply-templates select="node()|@*"/> </xsl:template> </xsl:stylesheet> >> -----Original Message----- >> From: Michael Kay [mailto:mhkay@xxxxxxxxxxxx] >> Sent: Thursday, January 25, 2001 2:58 AM >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx >> Subject: RE: [xsl] xsl to echo input xml >> >> >> > If I want to pass an xml to an xsl, and then have the xsl >> > simply repeat >> > what's in the xml, how would I go about that? >> >> <xsl:copy-of select="*"/> >> >> > I thought the following would do it: >> > >> > <xsl:template match="*"> >> > <xsl:apply-templates/> >> > </xsl:template> >> > >> No, this will copy the text nodes to the output but not the >> element nodes. >> I.E, the output will contain no tags. >> >> Mike Kay >> >> >> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list >> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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