Subject: RE: [xsl] Finding another element with the same name as the current node From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Fri, 2 Feb 2001 09:54:14 -0000 |
> When you use name() without any arguments, it gives you the name > (technically the 'expanded name') of the *context node*. Ooh, a rare mistake from Jeni, I can't resist leaping in with a correction! name() returns a QName for the node, not an expanded name. An expanded name consists of a (namespace URI, local name) pair, and there is no defined way of expressing an expanded name as a string. A QName has the form [prefix:]local-name; the prefix will be one that corresponds to the namespace URI, which usually means it will be the same prefix as you used in your source document. Mike Kay > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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