RE: [xsl] sorting question

Subject: RE: [xsl] sorting question
From: "Michael Kay" <mhkay@xxxxxxxxxxxx>
Date: Wed, 7 Mar 2001 21:10:49 -0000
> I'm trying to transform a list of elements into a sorted set
> of pairs, and
> haven't
> been able to determine how to get the 'next' sorted element
> relative to the current position.

This definitely calls for a two-pass approach, one to sort the data and the
second to group it.

> I checked out the xsl faq, and I found a posting of
> Jeni's that showed how to copy a sorted list into a variable, but
> it doesn't seem to be working for me.
> (I'm using MSXML3 in case that matters...)
> <xsl:variable name="letterlist">
>  <xsl:for-each select="/ALPHABET/LETTER">
>   <xsl:sort select="." />
>   <xsl:copy-of select="." />
>  </xsl:for-each>
> </xsl:variable>
> <!-- nothing comes out... -->
> <xsl:value-of select="$letterlist" />
It should, I think, be the concatenation of the letters.

Mike Kay
Software AG

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