[xsl] about xsl:when

[dago@xxxxxxxxxxxxxxxxx]

Hi all,

I try that display the names that have the 'id=1' and 'id=2' in the resutl,
but doesen't work.  In the XML file, each 'persona' node have a 'id' with
numeric value. This is the xsl code:

<xsl:template match = "persona[@id]" > 
  <xsl:choose > 
    <xsl:when test = ".='1'" > <br/>
      edad=<xsl:value-of select="name"/> 
    </xsl:when> 
    <xsl:when test = ".='2'" > <br/>
      edad=<xsl:value-of select="name"/> 
    </xsl:when> 
    <xsl:otherwise > <br/>
      <xsl:text >no hay</xsl:text> 
    </xsl:otherwise> 
  </xsl:choose> 
</xsl:template> 


Thnanks for you help,

Dago Flores.


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list