Subject: [xsl] why doesn't this do what i think it should? From: Michael Case <mecase@xxxxxxxxxxx> Date: Fri, 09 Mar 2001 12:11:26 -0800 |
Hi, Why doesn't this do what I think it should? Why is the result not enclosed in <newaaa></newaaa>? I am using TestXSLT from Xalan 1.0. Thanks for your help. Mike Case XML: <aaa> <bbb> <ccc> </ccc> <ccc> </ccc> <ccc> </ccc> </bbb> <bbb> <ccc> </ccc> </bbb> <bbb> <ccc> </ccc> </bbb> <lots-of-other-tags> </lots-of-other-tags> </aaa> XSLT: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns="http://www.w3.org/TR/xhtml1/strict" version="1.0"> <!-- It copies out the bbb's --> <newaaa> <xsl:strip-space elements="*"/> <xsl:output method = "xml"/> <xsl:template match="los-of-other-tags"></xsl:template> <xsl:template match="bbb"> <xsl:copy-of select="self::*"/> <xsl:apply-templates/> </xsl:template> </newaaa> </xsl:stylesheet> What I get: <?xml version="1.0" encoding="UTF-8"?> <bbb> <ccc> </ccc> <ccc> </ccc> <ccc> </ccc> </bbb> <bbb> <ccc> </ccc> </bbb> <bbb> <ccc> </ccc> </bbb> -- Michael E. Case UC Davis case@xxxxxxxxxxxxxxxxxx (530) 754-7226 XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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