Subject: Antwort: [xsl] copying source tree From: "Ulrich Becker" <ulrich.becker@xxxxxx> Date: Wed, 14 Mar 2001 16:50:02 +0100 |
You aren't copying anything without xsl:copy or xsl:copy-of. <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> and i think you want : <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> (It will work without also.) Bye Uli (Sorry, if I'm writing silly stuff. I'm only a newbie too and i use easy questions as exercises.) Shouldn't the following copy source to the result tree? <xsl:template match="@*|node()" > <xsl:apply-templates select = "@*|node()"/> </xsl:template> <xsl:template match="/"> <xsl:apply-templates select="*" /> </xsl:template> I want to make changes only to a node in the source tree by matching in the second template. This one does not seem to copy the source tree. _________________________________________________________________ -- Diese E-Mail enthält vertrauliche und/oder rechtlich geschützte Informationen. Wenn Sie nicht der richtige Adressat sind oder diese E-Mail irrtümlich erhalten haben, informieren Sie bitte sofort den Absender und vernichten Sie diese Mail. Das unerlaubte Kopieren sowie die unbefugte Weitergabe dieser Mail ist nicht gestattet. This e-mail may contain confidential and/or privileged information. If you are not the intended recipient (or have received this e-mail in error) please notify the sender immediately and destroy this e-mail. Any unauthorised copying, disclosure or distribution of the material in this e-mail is strictly forbidden. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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