Subject: [xsl] Reverse order From: Dan Diebolt <dandiebolt@xxxxxxxxx> Date: Tue, 1 May 2001 06:54:56 -0700 (PDT) |
>i am trying to list the parts of a book in reverse order. Kill the predicate (ie []) in your for-each and place the following as the first line in the body: <xsl:sort select="position()" data-type="number" order="descending"/> Regards, Dan ------ File: ReverseOrder.xml <?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="ReverseOrder.xsl"?> <book> <part><title>foo</title></part> <part><title>bar</title></part> <part><title>huhu</title></part> </book> File: ReverseOrder.xsl <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="book"> <xsl:for-each select="part"> <xsl:sort select="position()" data-type="number" order="descending"/> <xsl:value-of select="title"/><br/> </xsl:for-each> </xsl:template> </xsl:stylesheet> __________________________________________________ Do You Yahoo!? Yahoo! Auctions - buy the things you want at great prices http://auctions.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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