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Re: [xsl] Reverse order

Subject: Re: [xsl] Reverse order
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 1 May 2001 15:05:44 +0100
> I thought the XPath expression in the for-each statement should return a 
> reverse oder of all parts

No, it returns a node set, and sets are unordered.
for-each always iterates through the supplied node set in document
order... unless you supply an xsl:sort element you can reverse the order
with the order attribute on xsl:sort.

David

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