Subject: [xsl] Question about xsl-xslt From: Saverio Niccolini <s.niccolini@xxxxxxxxxxxx> Date: Tue, 22 May 2001 11:27:14 +0200 |
Dear all, I'm new in xml world so pease forgive me if my question is a silly one I'd like to define and test a variable in my xslt stylesheet but it didn't work: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:variable name="level" select="3"></xsl:variable> <xsl:choose> <xsl:when test="$level=3"> <xsl:value-of select="/filevideo/campi/campo1"> </xsl:value-of> </xsl:when> </xsl:choose> </xsl:template> It doesn't work because xslt doesn't recognize xsl:choose and xsl:when which belengs to xsl namespace? How may I make it work? I have to define two namespace in my xml document or what? Please any comment is well accepted Thanks in advance Saverio XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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