Subject: Re: [xsl] Question about xsl-xslt From: Dennis Thomas <dthomas@xxxxxxxxx> Date: Tue, 22 May 2001 11:29:25 -0700 |
Hi Saverio, The problem is in the defination of <xsl:variable name="level" select="3"></xsl:variable> When u define the select="3" its looking for a element node 3. Rather if u want to store a value u need to declare it as --> select="'3'" The declaration would now look as <xsl:variable name="level" select="'3'"></xsl:variable> take care, dennis Saverio Niccolini wrote: > Dear all, > > I'm new in xml world so pease forgive me if my question is a silly one > I'd like to define and test a variable in my xslt stylesheet but it > didn't work: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> > <xsl:template match="/"> > <xsl:variable name="level" select="3"></xsl:variable> > <xsl:choose> > <xsl:when test="$level=3"> > <xsl:value-of select="/filevideo/campi/campo1"> > </xsl:value-of> > </xsl:when> > </xsl:choose> > </xsl:template> > > It doesn't work because xslt doesn't recognize xsl:choose and xsl:when > which belengs to xsl namespace? > How may I make it work? I have to define two namespace in my xml > document or what? > > Please any comment is well accepted > Thanks in advance > Saverio > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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