Subject: RE: [xsl] How to sort a nodeset referenced by a variable? From: Kumar.Shailendra@xxxxxxxxxxxxxxxxx Date: Thu, 5 Jul 2001 11:19:32 -0400 (EDT) |
Hi Mike, Thanks for the response I got it working. I changed the sort key from <xsl:sort select="$fileterNode/secondElement"> to <xsl:sort select="./secondelement" /> It started working. I think now I understand your point. regards, Shailendra On Wed, 4 Jul 2001, Michael Kay wrote: > > I am doing something like this > > > > <xsl:variable name="filterdNode" select="//*" /> > > > > <xsl:variable name="sortedList"> > > <xsl:for-each select="$filterNode/someElement"> > > <xsl:sort select="$fileterNode/secondElement"> > > The value of your sort key will be the same for every node in the > collection. It's meaningless to use a sort key whose value doesn't depend on > the context node. > > Mike Kay > Software AG > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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