Subject: AW: [xsl] Beginner's question From: "Michael Schafer" <MSchaefer@xxxxxxxxxxxx> Date: Thu, 12 Jul 2001 12:37:33 +0200 |
Hello Chris, try this: <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*" /> </xsl:copy> </xsl:match> <xsl:template match="code"> </xsl:template> -----Ursprungliche Nachricht----- Von: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]Im Auftrag von J S Publications Gesendet: Donnerstag, 12. Juli 2001 10:25 An: XSL-List@xxxxxxxxxxxxxxxxxxxxxx Betreff: [xsl] Beginner's question Hi Here is a simple question from an absolute beginner! Suppose I have an XML document with a complex DTD. The DTD contains a tag deep in the hierarchy called <code>. How would I transform the XML doc to another XML doc that was identical except for having the <code> tag removed? I said it was a simple question! Chris XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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