Subject: [xsl] simple question with <xsl:copy-of> From: "Roman Huditsch" <r.huditsch@xxxxxxxx> Date: Tue, 17 Jul 2001 16:31:53 +0200 |
Hi alltogther! I've just a simple questtion: How can I copy all the tags from the body of my XML-source document into my XSL-stylesheet in order of their occurance and additionally adapt some of these tags with additional templates? I thought that I could make it with a simple <xsl:copy-of>, but the I just get all the text nodes.... <xsl:template match="body"> <form method="post"> <xsl:attribute name="action"> <xsl:value-of select="$all"/> </xsl:attribute> <xsl:copy-of select="."/> <xsl:apply-templates/> </form> </xsl:template> <xsl:template match="foo"> ..... </xsl:template> Could you please help me? Yours, Roman > Roman Huditsch (RH ) > _____________________________________________________________________ > hico Informations- und Kommunikations-Management Gesellschaft m.b.H. > TechLab, Thomas A. Edison Straße 2. > A-7000 Eisenstadt / Austria > phone: +43/2682/704-61-00; fax: +43/2682/704-71-61-10 > e-mail:support@xxxxxxxx; r.huditsch@xxxxxxxx > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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