Subject: Re: [xsl] Conditional variable assignment with node-set as value From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 18 Jul 2001 09:22:59 +0100 |
> select="saxon:node-set(RFQDomainAttributeDefinition[@Domain > = 'lbid']/ExtendedAttributeDefinition)" /> You can't use (and don't need) node-set there: node-set() converts a result tree fragment to a node set, but an XPath expression always returns a node set (or at least, it never returns a result tree fragment). If you remove all occurrences of saxon:node-set then your code looks right. On th eother hand If what you want is a node set as a result you would be better to use xsl:variable with a select expression rather than content, otherwise you will have to use saxon:node-set($extended-attrs-bid) every time you use it. It looks likey you just want <xsl:variable name="x" select="normalize-space(RFQDomainAttributeDefinition)"/> <xsl:variable name="extended-attrs-bid" select=" RFQDomainAttributeDefinition[$x][@Domain = 'lbid']/ExtendedAttributeDefinition | Bid[not($x)]/ExtendedAttribute[generate-id() = generate-id(key('extended-attrs-bid-index', @ExtendedAttributeCode))] "/> David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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