Subject: RE: [xsl] Position of a result tree fragment From: "Chris Bayes" <Chris@xxxxxxxxxxx> Date: Thu, 19 Jul 2001 00:55:49 +0100 |
Larry, Add it's original position to the rtf when you make it. Ciao Chris XML/XSL Portal http://www.bayes.co.uk/xml >-----Original Message----- >From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx >[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Laurence O >Garfield >Sent: 19 July 2001 00:08 >To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx >Subject: [xsl] Position of a result tree fragment > > >If I am passing a result tree fragment from one template to another using >a variable, is there any way to determine what the fragment's position >within its parent was originally? According to the XSLT spec I can't use >/, //, or [] on result tree fragments, so I can't use [position()]. Is >there some other way, or do I have to pass the position of the node >through as a second variable as well? > >--Larry Garfield >lgarfiel@xxxxxxxxxxxxxxxxxxx > >DePaul Linux Users Group Secretary > >-- "If at first you don't succeed, skydiving isn't for you." :-) > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Position of a result tree fra, Laurence O Garfield | Thread | RE: [xsl] Position of a result tree, Michael Kay |
[xsl] Shorthand for XPath expressio, William Bagby | Date | RE: [xsl] Shorthand for XPath expre, Chris Bayes |
Month |