Subject: RE: [xsl] Position of a result tree fragment From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Thu, 19 Jul 2001 03:20:03 +0100 |
A result tree fragment does not have a parent. Mike Kay Software AG > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Laurence O > Garfield > Sent: 19 July 2001 00:08 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Position of a result tree fragment > > > If I am passing a result tree fragment from one template to > another using > a variable, is there any way to determine what the fragment's position > within its parent was originally? According to the XSLT spec > I can't use > /, //, or [] on result tree fragments, so I can't use > [position()]. Is > there some other way, or do I have to pass the position of the node > through as a second variable as well? > > --Larry Garfield > lgarfiel@xxxxxxxxxxxxxxxxxxx > > DePaul Linux Users Group Secretary > > -- "If at first you don't succeed, skydiving isn't for you." :-) > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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