Subject: Re: [xsl] position within same nodes From: Laurence O Garfield <lgarfiel@xxxxxxxxxxxxxxxxxxx> Date: Thu, 19 Jul 2001 14:59:57 -0500 (CDT) |
> Larry, > > Try (count(preceding-sibling::meep)+1), or > (count(preceding-sibling::*[name()=name(current())])+1) for the general case. > > <xsl:number/> is another way to go. It can get fairly complex (look it up > in the spec), but in this case you shouldn't need any attributes to > configure the counting: it'll default to what you want. Bind it to a > variable if you need to retrieve it through XPath. > > Cheers, > Wendell Thanks, Wendell! They both worked perfectly. I decided to go with <xsl:number /> because it seemed more elegant/readable-1-year-from-now. :-) --Larry Garfield XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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