Subject: Re: [xsl] how to changing context From: David Carlisle <davidc@xxxxxxxxx> Date: Sun, 22 Jul 2001 21:39:18 +0100 |
I have a XSLT page to transform a.xml as well as an XML file referenced by document('b.xml') in the XSLT program, i wrote: <xsl:template match="/"> <!-- the root of a.xml --> <xsl:for-each select="document('b.xml')/root/subroot"/> <!-- here I want to reference to both the nodes under EACH "subroot" of b.xml and the nodes that are under the "/"node of a.xml> </xsl:for-each> </xsl:template> how can i change context inside <xsl:for-each>? (better without the help of variable/param You need to say how (and yhy) you want to refererence a and b. As others have said, if you make two variables to contain each of the root nodes you can always refer to nodes in eother of the two documents, but if you just meant that you want to process both sets of nodes then you can put nodes from both documents into the current node list with. eg changing your for-each to <xsl:for-each select="document('b.xml')/root/subroot|*"/> David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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