Subject: Re: [xsl] How to output attribute without namespace From: Jeni Tennison <mail@xxxxxxxxxxxxxxxx> Date: Fri, 7 Sep 2001 09:25:56 +0100 |
Hi Dmitri, > It works.But the problem that i have is i don't know the local-name > of attribute.... You can work out the local name of an attribute with the local-name() function. Try: <!-- match all attributes in the param namespace --> <xsl:template match="@param:*"> <!-- create an attribute of that name in no namespace --> <xsl:attribute name="{local-name()}"> <xsl:value-of select="." /> </xsl:attribute> </xsl:template> I hope that helps, Jeni --- Jeni Tennison http://www.jenitennison.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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