Subject: RE: [xsl] Getting the latest date From: Bas Alberts <bas.alberts@xxxxxxxxxxxx> Date: Wed, 12 Sep 2001 13:55:40 +0200 |
Since your dates are suitable for lexicographical ordering, how about the following (almost literally copied from http://www.dpawson.co.uk/xsl/sect2/N6461.html#d194e703): <xsl:template match="/"> <xsl:variable name="maximum"> <xsl:for-each select="//revision"> <xsl:sort select="@date" order="descending" /> <xsl:if test="position() = 1"> <xsl:value-of select="."/> </xsl:if> </xsl:for-each> </xsl:variable> <html> <body> <xsl:value-of select="$maximum"/> </body> </html> </xsl:template> Greetings, bas.alberts@xxxxxxxxxxxx -----Original Message----- From: Gustaf Liljegren [mailto:gustaf.liljegren@xxxxxx] Sent: Wednesday, September 12, 2001 13:46 To: XSL List Subject: [xsl] Getting the latest date In a DTD I collect meta information about a document's history, like this: <revision date="2000-04-19">1.0A</revision> <revision date="2000-04-20">1.0B</revision> <revision date="2000-04-21">1.0C</revision> I need a way to pick out the latest date from these. The latest revision is usually put on top of the others, but this may not always be the case. I have considered converting the string "2000-04-19" to the number "20000419" and then using the ceiling() function to get the latest date, but I'm looking for a less complicated way of doing this. Regards, Gustaf Liljegren XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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