Subject: [xsl] outputing a non existant element. From: Auguste Oumar <oumar_a@xxxxxxxx> Date: Wed, 12 Sep 2001 19:17:55 +0200 (CEST) |
Hi, i have one optional element in my schema-file say: <fruit>orange</fruit>.The default value of fruit is "apple".I would like to have a xslt-transformation which gives me the content of the fruit element if it appears in the xml-file or its default value if it doesn't appear.I have problem giving out the default value when the element doesn't appear in the xml-file.How can i solve it ? Thanks for help. Auguste __________________________________________________________________ Do You Yahoo!? Gesendet von Yahoo! Mail - http://mail.yahoo.de XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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