Subject: RE: [xsl] How do you get the non-transformed character entity out of MSXML3.0 From: jdgarrett@xxxxxxxxxx Date: Mon, 17 Sep 2001 06:24:19 -0500 |
Julian The vb COM objects are consuming the values of the attributes ....and I thought one of the primary purposes of XML was to be able to consume values of attributes and nodes and that the MSXML parser was the tool de-force by which one accomplished that.... Thanks Jim |-----Original Message----- |From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx |[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Julian |Reschke |Sent: Sunday, September 16, 2001 3:54 PM |To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx |Subject: RE: [xsl] How do you get the non-transformed character entity |out of MSXML3.0 | | |I'm still not sure about which problem you're trying to solve. | |It sounds like you want move information from one DOM into another? Why not |just import and append the DOM nodes without going through XML |serialization/parsing??? | |> -----Original Message----- |> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx |> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of |> jdgarrett@xxxxxxxxxx |> Sent: Sunday, September 16, 2001 8:53 PM |> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx |> Subject: RE: [xsl] How do you get the non-transformed character entity |> out of MSXML3.0 |> |> |> Julian (and thanks again Chris ) |> |> Julian problem (which Chris has enlightened me about,) |> is I want the value of the attribute or the element |> before transformation so that it can be inserted into |> another xml structure so that new xml structure is |> "loadable" by the dom via visual basic..."without" |> having to do the string manipulation that Chris |> provided in his first reply .....this way new |> xml and subsequent xml structures can be loaded |> in the dom via visual basic and passed around |> between vb COM objects until the final xml |> structure is transformed via the transformnode |> method in vb and sent out to the requesting browser |> as HTML .... |> |> the issue is keeping and accessing the value < (or other character |> entities) in their untransformed state (whether as an attribute value |> or a node value) when passing between vb COM objects without |> having to resort to additional string manipulations.... |> |> I have a simple vb function that will detransform a node or |> attribute value when the submitting browser submits a html form... |> using a simple replace function |> e.g. |> |> Function Detransform(submittedString) as string |> submittedString = replace(submittedString, "<", "<) |> submittedString = replace(submittedString, ">", ">) |> submittedString = replace(submittedString, "&", "&) |> submittedString = replace(submittedString, "'", "') |> submittedString = replace(submittedString, """","") |> Detransform = submittedString |> End Function |> |> |> now after the destransform occurs I did not want to have |> to run the xml through the above again every time the |> xml structure was loaded by the MSXML parser inside of |> all the vb COM objects that handle the XML structure on |> the way to the SQL db and back up the vb COM chain |> to the vb IIS application that does the final |> transformation into HTML and then response.write |> it out to the requesting browser... |> |> Now that Chris has informed me that it is not possible to |> access only the value rather than the value and the attribute |> name via MSXML from visual basic I will have to call |> the Detransform function every time the xml structure |> is loaded and the attribute value is accessed ... |> |> given (again) |> |> <Customer number="125487" NumberOfPurchases="<4" >Joe & Bill's |> Shop</Customer> |> |> It would be nice if the Detransform function was a native |> method inside the MSXML parser so that I could just access |> the detransformed value of the attribute .. |> |> dim stringDetransformedValue |> |> stringDetransformedValue = |> xml.selectSingleNode("/Customer/@NumberOfPurchases").xmlAttributeV |> alueNotTra |> nsformed |> |> which would return only |> |> <4 |> |> rather than |> |> NumberOfPurchases="<4" |> |> |> Bottom line .... |> |> I must then have an external from parser function |> |> given |> <Customer number="125487" NumberOfPurchases="<4" >Joe & Bill's |> Shop</Customer> |> |> '//call vb function |> result = |> ReturnAttributeValueOnly(xml.selectSingleNode("/Customer/@NumberOf |> Purchases" |> ).xml) |> |> |> Function ReturnAttributeValueOnly(ByVal stringPassedIn) As String |> Dim string1 As String |> Dim position1%, position2% |> position1% = InStr(1, stringPassedIn, """", 1) |> position2% = InStrRev(stringPassedIn, """") |> ReturnAttributeValueOnly = Mid$(stringPassedIn, position1 + 1, |position2 - |> (position1 + 1)) |> |> End Function |> |> the returned value would then be |> |> <4 |> |> Well that is that I guess ...(hey MS wanna put a new function in |the MSXML |> parser *s*) |> |> Thanks again Chris ....!!!!! |> |> |> |> |> |> |-----Original Message----- |> |From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx |> |[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Chris Bayes |> |Sent: Sunday, September 16, 2001 6:27 AM |> |To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx |> |Subject: RE: [xsl] How do you get the non-transformed character entity |> |out of MSXML3.0 |> | |> | |> |Julian, |> |Who knows what exactly the problem is here but suppose you wanted to do |> |something like find all records in a text file that match some attribute |> |in the dom. You can't do it. The text file might be a csv but with |> |escaped characters who knows but there are times when you want to get |> |"<4" from the dom so that you can match it to a record in a text |> |file. There is no way you can match a text record like |> |125487 <4 Joe & Bill's Shop |> |unless you can get the value "<4" out of the dom. |> | |> |Ciao Chris |> | |> |XML/XSL Portal |> |http://www.bayes.co.uk/xml |> | |> | |> |> -----Original Message----- |> |> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx |> |> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of |> |> Julian Reschke |> |> Sent: 16 September 2001 11:04 |> |> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx |> |> Subject: RE: [xsl] How do you get the non-transformed |> |> character entity out of MSXML3.0 |> |> |> |> |> |> Why would you want that? |> |> |> |> In XML, "less-than" is serialized as "<". |> |> |> |> When accessing the DOM, you get the "raw" character ("<"). |> |> |> |> Serializing the DOM again (using save() or the xml property) |> |> will turn it back into "<". |> |> |> |> I fail to see a problem here. |> | |> | |> | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list |> | |> |> |> |> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list |> | | | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list | XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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