Subject: [xsl] sort parameter problem From: Guillaume Rousse <rousse@xxxxxxxxxxxxxx> Date: Mon, 24 Sep 2001 17:21:55 +0200 |
The following construct hasn't any sort effect when called with sort=bar parameter: <xsl:template name="list-foos"> <xsl:param name="sort"/> <xsl:for-each select="foos/foo"> <xsl:sort select="$sort"/> [..] </xsl:for-each> </xsl:template> However, hardcoding sort value is OK: <xsl:template name="list-foos"> <xsl:param name="sort"/> <xsl:for-each select="foos/foo"> <xsl:sort select="bar"/> [..] </xsl:for-each> </xsl:template> The XSL spec says: xsl:sort has a select attribute whose value is an expression. So, am i doing something wrong there, or should i report a bug in xalan-j 2.2.D10 ? -- Guillaume Rousse <rousse@xxxxxxxxxxxxxx> GPG key http://lis.snv.jussieu.fr/~rousse/gpgkey.html XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Re: XPath Question (correctio, Dimitre Novatchev | Thread | RE: [xsl] sort parameter problem, Michael Kay |
Re: [xsl] XPath Question (correctio, cutlass | Date | [xsl] No defaut possible namespace , Guillaume Rousse |
Month |