Subject: RE: [xsl] Get parent's node position - Urgent From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Wed, 26 Sep 2001 21:28:05 +0100 |
> Ok Mike, thanks a lot. Excellent!!! > And what I would make to get a position of grand-parent?? > select="count(parent::*/parent::*/preceding-sibling::*)" of course. Or you can abbreviate parent::* to ".." Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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