[xsl] Re: sum of the evaluated values

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

> i have xml:
>   <event type="1" time="3:00">
>   <event type="0" time="2:00">
>   <event type="1" time="4:00">
>   <event type="1" time="5:00">
> and i need sum of the minutes: number(substring-before(@time,':'))
> only where @type=1.
> 
> How it can  be done?

Yet aother application for the transform-and-sum template 
(see http://sources.redhat.com/ml/xsl-list/2001-11/msg00831.html )

Here's how you could use it:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:func-transform="f:func-transform"
exclude-result-prefixes="xsl func-transform"
>
   <xsl:import href="transform-and-sum.xsl"/>

   <xsl:output method="text"/>
   
   <func-transform:func-transform/>

    <xsl:template match="/">
      <xsl:call-template name="transform-and-sum">
        <xsl:with-param name="pFuncTransform" 
                        select="document('')/*/func-transform:*[1]"/>
        <xsl:with-param name="pList" select="/*/*/@time"/>
      </xsl:call-template>
    </xsl:template>
    
    <xsl:template match="func-transform:*">
      <xsl:param name="arg" select="0"/>
      <xsl:value-of select="substring-before($arg, ':')"/>
    </xsl:template>

</xsl:stylesheet>

This when applied on your xml source (corrected to be weel-formed):

<events>
  <event type="1" time="3:00"/>
  <event type="0" time="2:00"/>
  <event type="1" time="4:00"/>
  <event type="1" time="5:00"/>
</events>

gives the following result:

14


Hope this helped.

Cheers,
Dimitre Novatchev.



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