Subject: [xsl] outputting an <a href> with a URL which contains "&func" From: Saverio Perugini <sperugin@xxxxxxxxxxxxxxxx> Date: Mon, 21 Jan 2002 17:36:42 -0500 (EST) |
Hello, I'm trying to output an <a href> from an XSL template. The value of the href attribute is a URL which contains the string ``&func'' The following results in an error regarding the reference to entity "func". The error states that the reference must end with the ';' delimiter. <a><xsl:attribute name="href"><xsl:text disable-output-escaping="yes">http://....?dtype=C&func=front&state=&style="></xsl:text></xsl:attribute></a> I have been able to circumvent this error with the following code. <a><xsl:attribute name="href"><xsl:text disable-output-escaping="yes"><![CDATA[http://....?dtype=C&func=front&state=&style=]]></xsl:text></xsl:attribute> Is this the correct method to achieve my desired result? Thank You, Saverio Perugini XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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